Answer
$(v^5-5)^2$
Work Step by Step
The first term is $v^5$ squared, the last term is $5$ squared, and the middle term is twice the negative product of these two terms. Now we can factor the trinomial into a binomial squared.
$v^{10}-10v^5+25$
$=(v^5-5)(v^5-5)$
$=(v^5-5)^2$