Intermediate Algebra: Connecting Concepts through Application

Published by Brooks Cole
ISBN 10: 0-53449-636-9
ISBN 13: 978-0-53449-636-4

Chapter 3 - Exponents, Polynomials and Functions - 3.5 Special Factoring Techniques - 3.5 Exercises - Page 279: 3

Answer

$(3g+2)^2$

Work Step by Step

The first term is $3g$ squared, the last term is $2$ squared, and the middle term is twice the product of these two terms. Now we can factor the trinomial into a binomial squared. $9g^2+12g+4$ $=(3g+2)^2$
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