Intermediate Algebra: Connecting Concepts through Application

Published by Brooks Cole
ISBN 10: 0-53449-636-9
ISBN 13: 978-0-53449-636-4

Chapter 3 - Exponents, Polynomials and Functions - 3.5 Special Factoring Techniques - 3.5 Exercises: 18

Answer

$(3d-4)(9d^2+12d+16)$

Work Step by Step

Use the formula $a^3-b^3=(a-b)(a^2+ab+b^2)$ to factor. $27d^3-64$ $=(3d-4)(9d^2+12d+16)$
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