Answer
$= 6a^{2}bc(4ab - 3bc + 5)$
Work Step by Step
$24a^{3}b^{2}c - 18a^{2}b^{2}c^{2} +30a^{2}bc$
$= 6a^{2}bc(4ab - 3bc + 5)$
Intermediate Algebra: Connecting Concepts through Application
by Clark, Mark; Anfinson, Cynthia
Published by
Brooks Cole
ISBN 10:
0-53449-636-9
ISBN 13:
978-0-53449-636-4
Chapter 3 - Exponents, Polynomials and Functions - 3.4 Factoring Polynomials - 3.4 Exercises - Page 270: 12
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