Intermediate Algebra: Connecting Concepts through Application

Published by Brooks Cole
ISBN 10: 0-53449-636-9
ISBN 13: 978-0-53449-636-4

Chapter 3 - Exponents, Polynomials and Functions - 3.3 Composing Functions - 3.3 Exercises - Page 259: 49

Answer

$\text{a) } f(3)+g(3)=-15 \\\\\text{b) } f(4)g(4)=-420 \\\\\text{c) } f(g(7))=-134$

Work Step by Step

$\bf{\text{Solution Outline:}}$ Substitute the given functions, \begin{array}{l}\require{cancel} f(x)= -9x+1 \\g(x)= x+8 ,\end{array} into the required operations. $\bf{\text{Solution Details:}}$ a) \begin{array}{l}\require{cancel} f(x)+g(x)=(-9x+1)+(x+8) \\\\ f(3)+g(3)=(-9(3)+1)+((3)+8) \\\\ f(3)+g(3)=(-27+1)+(3+8) \\\\ f(3)+g(3)=-26+11 \\\\ f(3)+g(3)=-15 \end{array} b) \begin{array}{l}\require{cancel} f(x)g(x)=(-9x+1)(x+8) \\\\ f(4)g(4)=(-9(4)+1)((4)+8) \\\\ f(4)g(4)=(-36+1)(4+8) \\\\ f(4)g(4)=(-35)(12) \\\\ f(4)g(4)=-420 \end{array} c) \begin{array}{l}\require{cancel} f(g(x))=f(x+8) \\\\ f(g(7))=f(7+8) \\\\ f(g(7))=f(15) \\\\ f(g(7))=-9(15)+1 \\\\ f(g(7))=-135+1 \\\\ f(g(7))=-134 \end{array} Therefore, \begin{array}{l}\require{cancel} \text{a) } f(3)+g(3)=-15 \\\\\text{b) } f(4)g(4)=-420 \\\\\text{c) } f(g(7))=-134 .\end{array}
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