Answer
$(4m^{3}n^{6}p^{2})^{\frac{1}{7}}=4^{\frac{1}{7}}m^{\frac{3}{7}}n^{\frac{6}{7}}p^{\frac{2}{7}}$
Work Step by Step
Step 1: The index of the radical is 7, so the denominator of the fractional exponent is 7.
Step 2: Therefore, the expression is written as $(4m^{3}n^{6}p^{2})^{\frac{1}{7}}$.
Step 3: $(4m^{3}n^{6}p^{2})^{\frac{1}{7}}=4^{\frac{1}{7}}m^{\frac{3}{7}}n^{\frac{6}{7}}p^{\frac{2}{7}}$
