Intermediate Algebra: Connecting Concepts through Application

Published by Brooks Cole
ISBN 10: 0-53449-636-9
ISBN 13: 978-0-53449-636-4

Chapter 1 - Linear Functions - 1.5 Finding Equations of Lines - 1.5 Exercises: 66

Answer

y=$\frac{1}{6}$x-$\frac{7}{3}$

Work Step by Step

6x+y=-11 y=-6x-11 The desired line must have a slope that is the opposite reciprocal of -6. Therefore, m=$\frac{1}{6}$. y-y$_1$=m(x-x$_1$) y+3=$\frac{1}{6}$(x+4) y=$\frac{1}{6}$x+$\frac{2}{3}$-3 y=$\frac{1}{6}$x-$\frac{7}{3}$
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