Intermediate Algebra: Connecting Concepts through Application

Published by Brooks Cole
ISBN 10: 0-53449-636-9
ISBN 13: 978-0-53449-636-4

Chapter 1 - Linear Functions - 1.5 Finding Equations of Lines - 1.5 Exercises - Page 74: 9

Answer

y=$-\frac{5}{4}x$ + $\frac{15}{2}$

Work Step by Step

Two points clearly on the line are (2,5) and (6,0). By moving across the line from one point to the next, we can clearly see that the slope goes down (negative) 5 and moves to the right 4 units, giving us a slope of m= $-\frac{5}{4}$. We can now use one of those points to find b: Plugging (6,0) into y=mx+b: 0=$-\frac{5}{4}(6)$ + b b=$\frac{15}{2}$ And our line is thus y=$-\frac{5}{4}x$ + $\frac{15}{2}$.
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.