Intermediate Algebra: Connecting Concepts through Application

Published by Brooks Cole
ISBN 10: 0-53449-636-9
ISBN 13: 978-0-53449-636-4

Chapter 1 - Linear Functions - 1.5 Finding Equations of Lines - 1.5 Exercises: 10

Answer

$y = \frac{15}{2}x$ -$\frac{15}{2}$

Work Step by Step

Two points clearly on the line are (1,0) and (3,15). By going from one point to the other, we see that we move up 15 units and to the right 2 units, giving us a rise/run slope of m= $\frac{15}{2}$. We can use one of these points to plug into y=mx+b to find b: y=mx+b 0=$\frac{15}{2}$(1)+b 0=$\frac{15}{2}$+b $-\frac{15}{2}$ = b And so our line is $y = \frac{15}{2}x$ -$\frac{15}{2}$.
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