Intermediate Algebra: Connecting Concepts through Application

Published by Brooks Cole
ISBN 10: 0-53449-636-9
ISBN 13: 978-0-53449-636-4

Chapter 1 - Linear Functions - 1.1 Solving Linear Equations - 1.1 Exercises - Page 14: 62

Answer

r=$\frac{17}{9}$

Work Step by Step

$\frac{2}{5}$(3r-8)=$\frac{3}{5}$(-4r+6) 2(3r-8)=3(-4r+6) 6r-16=-12r+18 18r=34 r=$\frac{17}{9}$
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