Intermediate Algebra: Connecting Concepts through Application

Published by Brooks Cole
ISBN 10: 0-53449-636-9
ISBN 13: 978-0-53449-636-4

Chapter 1 - Linear Functions - 1.1 Solving Linear Equations - 1.1 Exercises - Page 12: 30

Answer

a. $C=1000+400(d)$ b. 3000 dollars c. 6 days

Work Step by Step

a. $C=1000+400(d)$ b. $d=5$ $C=1000+400(5)$ $C=1000+2000$ $C=3000$ c. $C=3500$ $3500=1000+400(d)$ $3500-1000=400(d)$ $2500=400(d)$ $2500\div400=d$ $d=6.25$ $d=6$
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