Answer
a. $C=125+100(d)$
b. $C=425$
c. 2 days
Work Step by Step
a. $C=cost$ $d=days$
$C=125+100(d)$
b. $d=3$
$C=125+100(3)$
$C=125+300$
$C=425$
c. $C=700\div2=350$
$350=125+100(d)$
$350-125=100(d)$
$225=100(d)$
$225\div100=d$
$d=2.25$
$d=2$
Intermediate Algebra: Connecting Concepts through Application
by Clark, Mark; Anfinson, Cynthia
Published by
Brooks Cole
ISBN 10:
0-53449-636-9
ISBN 13:
978-0-53449-636-4
Chapter 1 - Linear Functions - 1.1 Solving Linear Equations - 1.1 Exercises - Page 12: 29
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