Intermediate Algebra: Connecting Concepts through Application

Published by Brooks Cole
ISBN 10: 0-53449-636-9
ISBN 13: 978-0-53449-636-4

Chapter 1 - Linear Functions - 1.1 Solving Linear Equations - 1.1 Exercises - Page 11: 24

Answer

a. 90 b. 270 c. 8000

Work Step by Step

a. $p=0.06(s-500)$ with $s=2000$ $p=0.06(2000-500)$ $p=0.06(1500)$ $p=90$ b. $p=0.06(s-500)$ with $s=5000$ $p=0.06(5000-500)$ $p=0.06(4500)$ $p=270$ c. $p=450$ $450=0.06(s-500)$ $450\div0.06=s-500$ $7500=s-500$ $7500+500=s$ $s=8000$
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