Intermediate Algebra: Connecting Concepts through Application

Published by Brooks Cole
ISBN 10: 0-53449-636-9
ISBN 13: 978-0-53449-636-4

Chapter 1-8 - Cumulative Review - Page 681: 96

Answer

$\frac{\sqrt {10y}}{5y}$

Work Step by Step

First, we need to cancel out common terms in the numerator and denominator: $\sqrt {\frac{2}{5y}}$ Separate the radical: $\frac{\sqrt {2}}{\sqrt {5y}}$ We don't want to leave radicals in the denominator, so to get rid of radicals in the denominator, we multiply both the numerator and denominator by the denominator: $\frac{\sqrt {2}}{\sqrt {5y}} • \frac{\sqrt {5y}}{\sqrt {5y}}$ Multiply to simplify: $\frac{\sqrt {10y}}{\sqrt {25y^2}}$ Take the square root of any perfect squares: $\frac{\sqrt {10y}}{5y}$
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