Intermediate Algebra: Connecting Concepts through Application

Published by Brooks Cole
ISBN 10: 0-53449-636-9
ISBN 13: 978-0-53449-636-4

Chapter 1-6 - Cumulative Review: 73

Answer

$= 60m^{6}n^{5}$

Work Step by Step

$(4m^{5}n^{3})(15mn^{2})$ $= 60m^{5}mn^{3}n^{2}$ $= 60m^{6}n^{5}$
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