Answer
$H^+=1\times10^{-6}$ M
Work Step by Step
$pH=6$
Putting in the formula
$pH=-\log(H^+)$
$6=-\log(H^+)$
$-\log(H^+)=6$
$\log(H^+)=-6$
$H^+=10^{-6}$ M
Intermediate Algebra: Connecting Concepts through Application
by Clark, Mark; Anfinson, Cynthia
Published by
Brooks Cole
ISBN 10:
0-53449-636-9
ISBN 13:
978-0-53449-636-4
Chapter 1-6 - Cumulative Review - Page 549: 71
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