Answer
$f^{-1}(x) = \frac{x-12}{3}$
Work Step by Step
$f(x) = 3x+12$
Let $f(x) = y$
$y = 3x+12$
Swap $x$ and $y$ and then solve for $y$.
$x = 3y + 12$
$x-12 = 3y$
$y = \frac{x-12}{3}$
$f^{-1}(x) = \frac{x-12}{3}$
Intermediate Algebra: Connecting Concepts through Application
by Clark, Mark; Anfinson, Cynthia
Published by
Brooks Cole
ISBN 10:
0-53449-636-9
ISBN 13:
978-0-53449-636-4
Chapter 1-6 - Cumulative Review - Page 549: 69
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