Intermediate Algebra: Connecting Concepts through Application

Published by Brooks Cole
ISBN 10: 0-53449-636-9
ISBN 13: 978-0-53449-636-4

Chapter 1-6 - Cumulative Review - Page 549: 61

Answer

$(5r-8t)(5r+8t)$

Work Step by Step

Use the differenvce of two squares formula $a^2-b^2=(a-b)(a+b)$: $25r^2-64t^2$ =$5^2r^2-8^2t^2$ =$(5r)^2-(8t)^2$ =$(5r-8t)(5r+8t)$
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