Intermediate Algebra: Connecting Concepts through Application

Published by Brooks Cole
ISBN 10: 0-53449-636-9
ISBN 13: 978-0-53449-636-4

Chapter 1-6 - Cumulative Review - Page 548: 33

Answer

$x \geq 3.2$

Work Step by Step

$3(4x-8) \geq2x+8$ $12x-24 \geq2x+8$ $12x-2x \geq 8+24$ $10x \geq 32$ $x \geq \frac{32}{10}=\frac{16}{5}$ $x \geq \frac{16}{5}=3.2$ $x \geq 3.2$
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