Intermediate Algebra: Connecting Concepts through Application

Published by Brooks Cole
ISBN 10: 0-53449-636-9
ISBN 13: 978-0-53449-636-4

Chapter 1-6 - Cumulative Review: 1

Answer

$x \approx 1.166$

Work Step by Step

$3(4.2)^{x} + 7 = 23$ $3(4.2)^{x} = 23 - 7$ $3(4.2)^{x} = 16$ $4.2^{x} = \frac{16}{3}$ $x = \log_{4.2} \frac{16}{3}$ $x = \frac{\log \frac{16}{3}}{\log 4.2}$ $x = 1.16646...$ $x \approx 1.166$ Check: $3(4.2)^{(1.166...)} + 7 \overset{?}{=} 23$ $16+ 7 \overset{?}{=} 23$ $23 = 23$
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