## Intermediate Algebra (6th Edition)

We are given that $g={(4,2), (-1,3), (5,3), (7,1)}$. We know that a function is one-to-one if each x-value of the function corresponds to only one y-value and each y-value corresponds to only one x-value. Therefore, this function is not one-to-one, because the y-value of 3 corresponds to more than one x-value (-1 and 5).