## Intermediate Algebra (6th Edition)

One-to-one, $f^{-1}={(6,-2), (8,4), (-6,2), (3,3)}$
We are given that $f={(-2,6), (4,8), (2,-6), (3,3)}$. This function is one-to-one, because each x-value corresponds to only one y-value and each y-value corresponds to only one x-value. We can find the inverse by interchanging the coordinates of each point. For example, the point (-2,6) will become (6,-2). Therefore, $f^{-1}={(6,-2), (8,4), (-6,2), (3,3)}$.