## Intermediate Algebra (6th Edition)

$\frac{x-6}{x^{2}+1}$
We know that $(\frac{f}{g})(x)=\frac{f(x)}{g(x)}$ (assuming that $g(x)\ne0$). Therefore, $(\frac{f}{g})(x)=\frac{f(x)}{g(x)}=\frac{x-6}{x^{2}+1}$