Intermediate Algebra (6th Edition)

Published by Pearson
ISBN 10: 0321785045
ISBN 13: 978-0-32178-504-6

Chapter 9 - Sections 9.1-9.6 - Integrated Review - Functions and Properties of Logarithms: 4

Answer

$\frac{x-6}{x^{2}+1}$

Work Step by Step

We know that $(\frac{f}{g})(x)=\frac{f(x)}{g(x)}$ (assuming that $g(x)\ne0$). Therefore, $(\frac{f}{g})(x)=\frac{f(x)}{g(x)}=\frac{x-6}{x^{2}+1}$
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