Intermediate Algebra (6th Edition)

Published by Pearson
ISBN 10: 0321785045
ISBN 13: 978-0-32178-504-6

Chapter 9 - Sections 9.1-9.6 - Integrated Review - Functions and Properties of Logarithms: 3

Answer

$x^{3}-6x^{2}+x-6$

Work Step by Step

We know that $(f\times g)(x)=f(x)\times g(x)$. Therefore, $(f\times g)(x)=f(x)\times g(x)=(x-6)\times(x^{2}+1)$. We can use the FOIL method to simplify. First= $x\times x^{2}=x^{1+2}=x^{3}$ Outer= $x\times1=x$ Inner= $-6\times x^{2}=-6x^{2}$ Last= $-6\times1=-6$ We can now add these terms together. $x^{3}+x+(-6x^{2})+(-6)=x^{3}-6x^{2}+x-6$
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