Answer
$x^{3}-6x^{2}+x-6$
Work Step by Step
We know that $(f\times g)(x)=f(x)\times g(x)$.
Therefore, $(f\times g)(x)=f(x)\times g(x)=(x-6)\times(x^{2}+1)$.
We can use the FOIL method to simplify.
First= $x\times x^{2}=x^{1+2}=x^{3}$
Outer= $x\times1=x$
Inner= $-6\times x^{2}=-6x^{2}$
Last= $-6\times1=-6$
We can now add these terms together.
$x^{3}+x+(-6x^{2})+(-6)=x^{3}-6x^{2}+x-6$
