Intermediate Algebra (6th Edition)

Published by Pearson
ISBN 10: 0321785045
ISBN 13: 978-0-32178-504-6

Chapter 9 - Section 9.5 - Logarithmic Functions - Exercise Set - Page 573: 100

Answer

$0$

Work Step by Step

Using $\log_b b=1$ and $\log_bx^y=y\log_bx$, the given expression, $ \log_7(\log_4 (\log_216)) ,$ simplifies to \begin{array}{l}\require{cancel} \log_7(\log_4 (\log_22^4)) \\\\= \log_7(\log_4 (4\log_22)) \\\\= \log_7(\log_4 (4\cdot1)) \\\\= \log_7(\log_4 4) \\\\= \log_7(1) \\\\= \log_71 \\\\= 0 .\end{array}
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