Intermediate Algebra (6th Edition)

Published by Pearson
ISBN 10: 0321785045
ISBN 13: 978-0-32178-504-6

Chapter 9 - Section 9.5 - Logarithmic Functions - Exercise Set: 92

Answer

$m-1$

Work Step by Step

Since the denominators are the same, add the numerators and copy the denominator. The given rational expression, $ \dfrac{m^2}{m+1}-\dfrac{1}{m+1} ,$ simplifies to \begin{array}{l}\require{cancel} \dfrac{m^2-1}{m+1} \\\\= \dfrac{(m+1)(m-1)}{m+1} \\\\= \dfrac{(\cancel{m+1})(m-1)}{\cancel{m+1}} \\\\= m-1 .\end{array}
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