Intermediate Algebra (6th Edition)

Published by Pearson
ISBN 10: 0321785045
ISBN 13: 978-0-32178-504-6

Chapter 9 - Section 9.5 - Logarithmic Functions - Exercise Set: 9

Answer

$\pi^{-2}=\frac{1}{\pi^{2}}$

Work Step by Step

If $b\gt0$ and $b\ne1$, then $y=log_{b}x$ means $x=b^{y}$ for every $x$ and every real number $y$. Therefore, $\log_{\pi}\frac{1}{\pi^{2}}=-2$ means $\pi^{-2}=\frac{1}{\pi^{2}}$.
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