## Intermediate Algebra (6th Edition)

Published by Pearson

# Chapter 9 - Section 9.5 - Logarithmic Functions - Exercise Set: 89

#### Answer

$\frac{2x+3}{x^{2}}$

#### Work Step by Step

We are given $\frac{2}{x}+\frac{3}{x^{2}}$. We can multiply the first term by $\frac{x}{x}$ (by which we are simply multiplying by 1) in order to give both fractions the same denominator. $(\frac{2}{x}\times\frac{x}{x})+\frac{3}{x^{2}}=\frac{2x}{x^{2}}+\frac{3}{x^{2}}=\frac{2x+3}{x^{2}}$

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