Intermediate Algebra (6th Edition)

Published by Pearson
ISBN 10: 0321785045
ISBN 13: 978-0-32178-504-6

Chapter 9 - Section 9.5 - Logarithmic Functions - Exercise Set: 62

Answer

$x=3$

Work Step by Step

If $b\gt0$ and $b\ne1$, then $y=log_{b}x$ means $x=b^{y}$ for every $x\gt0$ and every real number $y$. Therefore, $log_{x}27=3$ is equivalent to $x^{3}=27$. Now, take the cube root of both sides of $x^{3}=27$. $\sqrt[3] (x^{3})=\sqrt[3] 27$ $x=3$
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