Intermediate Algebra (6th Edition)

Published by Pearson
ISBN 10: 0321785045
ISBN 13: 978-0-32178-504-6

Chapter 9 - Section 9.3 - Exponential Functions - Exercise Set - Page 560: 74

Answer

Please see the graph.

Work Step by Step

$y=abs((1/3)^x)$ $x=0$ $y=abs((1/3)^x)$ $y=abs((1/3)^0)$ $y=abs(1)$ $y=1$ $x=1$ $y=abs((1/3)^x)$ $y=abs((1/3)^1)$ $y=abs(1/3)$ $y=1/3$ $(0,1)$ and $(1, 1/3)$ are on the curve.
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