Intermediate Algebra (6th Edition)

Published by Pearson
ISBN 10: 0321785045
ISBN 13: 978-0-32178-504-6

Chapter 9 - Section 9.3 - Exponential Functions - Exercise Set: 26



Work Step by Step

We are given that $9^{2x+1}=81$. Both of these numbers are powers of 9, so we can rewrite the equation as $9^{2x+1}=9^{2}$. From the uniqueness of $b^{x}$, we know that $b^{x}=b^{y}$ is equivalent to $x=y$ (when $b\gt0$ and $b\ne1$). Therefore, $2x+1=2$. Subtract 1 from both sides.. $2x=1$ Divide both sides by 2. $x=\frac{1}{2}$
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