## Intermediate Algebra (6th Edition)

$(0, k)$
The vertex form of a quadratic function is $y=a(x-h)^{2}+k$ with a vertex at $(h, k)$. The graph of $f(x)=x^{2}+k$ an be rewritten in vertex form, $f(x)=(x-0)^{2}+k$. Therefore the vertex is at $(0, k)$.