#### Answer

$(0, k)$

#### Work Step by Step

The vertex form of a quadratic function is $y=a(x-h)^{2}+k$ with a vertex at $(h, k)$. The graph of $f(x)=x^{2}+k$ an be rewritten in vertex form, $f(x)=(x-0)^{2}+k$. Therefore the vertex is at $(0, k)$.

Published by
Pearson

ISBN 10:
0321785045

ISBN 13:
978-0-32178-504-6

$(0, k)$

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