## Intermediate Algebra (6th Edition)

$x=-5 \pm2 \sqrt 3$
$(x+5)^{2}=12$ Square root both sides $(x+5)=\pm \sqrt 12$ Simplify the $\sqrt 12$ $x+5= \pm 2\sqrt 3$ Subtract 5 from both sides $x=-5 \pm2 \sqrt 3$