Intermediate Algebra (6th Edition)

Published by Pearson
ISBN 10: 0321785045
ISBN 13: 978-0-32178-504-6

Chapter 8 - Sections 8.1-8.3 - Integrated Review - Summary on Solving Quadratic Equations: 17

Answer

The solution set is $\left\{2-3\sqrt3, 2+3\sqrt3\right\}$.

Work Step by Step

Get the square root of both sides: $\sqrt{(x-2)^2} \pm \sqrt{27} \\x-2 = \pm \sqrt{9(3)} \\x-2 = \pm 3\sqrt{3}$ Add 2 to both sides: $x-2+2 = 2 \pm 3\sqrt{3} \\x=2 \pm 3\sqrt{3}$
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