Intermediate Algebra (6th Edition)

Published by Pearson
ISBN 10: 0321785045
ISBN 13: 978-0-32178-504-6

Chapter 8 - Section 8.1 - Solving Quadratic Equations by Completing the Square - Exercise Set - Page 485: 43

Answer

$y=-\dfrac{1}{2}\pm\dfrac{\sqrt{29}}{2}$

Work Step by Step

Using the completing the square method, then, \begin{array}{l} y^2+y-7=0\\ y^2+y=7\\ y^2+y+\left( \dfrac{1}{2} \right)^2=7+\left( \dfrac{1}{2}\right)^2\\ y^2+y+\dfrac{1}{4}=7+\dfrac{1}{4}\\ \left( y+\dfrac{1}{2} \right)^2=\dfrac{29}{4}\\ y+\dfrac{1}{2}=\pm\sqrt{\dfrac{29}{4}}\\ y=-\dfrac{1}{2}\pm\dfrac{\sqrt{29}}{2} .\end{array}
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.