## Intermediate Algebra (6th Edition)

x=$\frac{1±4i}{3}$
Original Equation (3x-1)²=-16 Take the square root of both sides 3x-1=±$\sqrt -16$ Simplify the radical 3x-1=±4i Add 1 to both sides 3x=1±4i Divide both sides by 3 x=$\frac{1±4i}{3}$