Intermediate Algebra (6th Edition)

Published by Pearson
ISBN 10: 0321785045
ISBN 13: 978-0-32178-504-6

Chapter 8 - Review - Page 531: 31

Answer

$[-5, 5]$

Work Step by Step

$2x^2-50 \le 0$ $2(x^2-25) \le 0$ $2(x^2-25)/2 \le 0/2$ $x^2-25 \le 0$ $(x+5)(x-5) \le 0$ $x+5=0$ $x+5-5=0-5$ $x=-5$ $x-5=0$ $x-5+5=0+5$ $x=5$ Three regions to test: $(-∞, -5]$, $[-5, 5]$, $[5, ∞)$ Let $x=-10$, $x=0$, $x=10$ $x=-10$ $2x^2-50 \le 0$ $2(-10)^2-50 \le 0$ $2*100-50 \le 0$ $200-50 \le 0$ $ 150 \le 0$ (false) $x=0$ $2x^2-50 \le 0$ $2*0^2-50 \le 0$ $2*0-50 \le 0$ $0-50 \le 0$ $-50 \le 0$ (true) $x=10$ $2x^2-50 \le 0$ $2(10)^2-50 \le 0$ $2*100-50 \le 0$ $200-50 \le 0$ $ 150 \le 0$ (false)
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