Intermediate Algebra (6th Edition)

Published by Pearson
ISBN 10: 0321785045
ISBN 13: 978-0-32178-504-6

Chapter 7 - Test - Page 470: 8

Answer

$a^{7/12}-a^{7/3}$

Work Step by Step

The given expression, $ a^{-2/3}\left( a^{5/4}-a^3 \right) ,$ simplifies to \begin{array}{l}\require{cancel} a^{\frac{-2}{3}}\cdot a^{\frac{5}{4}}+a^{\frac{-2}{3}}\cdot\left( -a^3 \right) \\\\= a^{\frac{-2}{3}+\frac{5}{4}}-a^{\frac{-2}{3}+3} \\\\= a^{\frac{-8}{12}+\frac{15}{12}}-a^{\frac{-2}{3}+\frac{9}{3}} \\\\= a^{\frac{7}{12}}-a^{\frac{7}{3}} \\\\= a^{7/12}-a^{7/3} .\end{array}
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