Answer
$3b^{3}$
Work Step by Step
$\sqrt[4] (81b^{12})=\sqrt[4] 81\times\sqrt[4] (b^{12})=3b^{3}$
We know that $\sqrt[4] 81=3$, because $3^{4}=81$. Also, we know that $\sqrt[4] (b^{12})=b^{3}$, because $(b^{3})^{4}=b^{3\times4}=b^{12}$.
Intermediate Algebra (6th Edition)
by Martin-Gay, Elayn
Published by
Pearson
ISBN 10:
0321785045
ISBN 13:
978-0-32178-504-6
Chapter 7 - Sections 7.1-7.5 - Integrated Review - Radicals and Rational Exponents - Page 446: 8
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