Intermediate Algebra (6th Edition)

Published by Pearson
ISBN 10: 0321785045
ISBN 13: 978-0-32178-504-6

Chapter 7 - Sections 7.1-7.5 - Integrated Review - Radicals and Rational Exponents: 8

Answer

$3b^{3}$

Work Step by Step

$\sqrt[4] (81b^{12})=\sqrt[4] 81\times\sqrt[4] (b^{12})=3b^{3}$ We know that $\sqrt[4] 81=3$, because $3^{4}=81$. Also, we know that $\sqrt[4] (b^{12})=b^{3}$, because $(b^{3})^{4}=b^{3\times4}=b^{12}$.
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