Intermediate Algebra (6th Edition)

Published by Pearson
ISBN 10: 0321785045
ISBN 13: 978-0-32178-504-6

Chapter 7 - Sections 7.1-7.5 - Integrated Review - Radicals and Rational Exponents: 5

Answer

$y^{3}$

Work Step by Step

$\sqrt[3] (y^{9})=y^{3}$ We know this because $(y^{3})^{3}=y^{3\times3}=y^{9}$.
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