Intermediate Algebra (6th Edition)

Published by Pearson
ISBN 10: 0321785045
ISBN 13: 978-0-32178-504-6

Chapter 7 - Sections 7.1-7.5 - Integrated Review - Radicals and Rational Exponents: 4

Answer

$x^{3}$

Work Step by Step

$\sqrt (x^{6})=x^{3}$ We know this because $(x^{3})^{2}=x^{3\times2}=x^{6}$.
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