Intermediate Algebra (6th Edition)

Published by Pearson
ISBN 10: 0321785045
ISBN 13: 978-0-32178-504-6

Chapter 7 - Sections 7.1-7.5 - Integrated Review - Radicals and Rational Exponents: 18

Answer

$\sqrt[4] (a^{3}b^{2})$

Work Step by Step

$\sqrt[12] (a^{9}b^{6})=(a^{9}b^{6})^{\frac{1}{12}}=a^{\frac{9}{12}}b^{\frac{6}{12}}=a^{\frac{3}{4}}b^{\frac{2}{4}}=\sqrt[4] (a^{3}b^{2})$
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