Chapter 7 - Sections 7.1-7.5 - Integrated Review - Radicals and Rational Exponents - Page 446: 17

$2x^{2}$

$\sqrt[3] (8x^{6})=(8x^{6})^{\frac{1}{3}}=8^{\frac{1}{3}}\times(x^{6})^{\frac{1}{3}}=8^{\frac{1}{3}}\times(x^{\frac{6}{3}})=8^{\frac{1}{3}}\times x^{2}=2x^{2}$ We know that $8^{\frac{1}{3}}=2$, because $2^{3}=8$.