## Intermediate Algebra (6th Edition)

Published by Pearson

# Chapter 7 - Sections 7.1-7.5 - Integrated Review - Radicals and Rational Exponents: 12

#### Answer

$\sqrt[5] ((x+1)^{3})$

#### Work Step by Step

We know that $a^{\frac{1}{n}}=\sqrt[n] a$ (where n is positive integer greater than 1 and $\sqrt[n] a$ is a real number). Therefore, $(x+1)^{\frac{3}{5}}=\sqrt[5] ((x+1)^{3})$

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