Intermediate Algebra (6th Edition)

Published by Pearson
ISBN 10: 0321785045
ISBN 13: 978-0-32178-504-6

Chapter 7 - Section 7.4 - Adding, Subtracting, and Multiplying Radical Expressions - Exercise Set - Page 438: 20

Answer

$-4\sqrt[3]{x}+7\sqrt{7}$

Work Step by Step

Using the properties of radicals, then, \begin{array}{l} 3\sqrt{7}-\sqrt[3]{x}+4\sqrt{7}-3\sqrt[3]{x} \\= (-\sqrt[3]{x}-3\sqrt[3]{x})+(3\sqrt{7}+4\sqrt{7}) \\= -4\sqrt[3]{x}+7\sqrt{7} .\end{array}
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