Answer
$\dfrac{3\sqrt[3]{4}}{14}$
Work Step by Step
Using the properties of radicals, then,
\begin{array}{l}
\dfrac{2\sqrt[3]{4}}{7}-\dfrac{\sqrt[3]{4}}{14}
\\\\=
\dfrac{2(2\sqrt[3]{4})-\sqrt[3]{4}}{14}
\\\\=
\dfrac{4\sqrt[3]{4}-\sqrt[3]{4}}{14}
\\\\=
\dfrac{3\sqrt[3]{4}}{14}
.\end{array}