Intermediate Algebra (6th Edition)

Published by Pearson
ISBN 10: 0321785045
ISBN 13: 978-0-32178-504-6

Chapter 7 - Section 7.4 - Adding, Subtracting, and Multiplying Radical Expressions - Exercise Set - Page 438: 1

Answer

$-2\sqrt{2}$

Work Step by Step

Using the properties of radicals, then, \begin{array}{l} \sqrt{8}-\sqrt{32} \\= \sqrt{4\cdot2}-\sqrt{16\cdot2} \\= 2\sqrt{2}-4\sqrt{2} \\= -2\sqrt{2} .\end{array}
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.