Intermediate Algebra (6th Edition)

Published by Pearson
ISBN 10: 0321785045
ISBN 13: 978-0-32178-504-6

Chapter 7 - Section 7.1 - Radicals and Radical Functions - Exercise Set - Page 418: 99

Answer

not a real number

Work Step by Step

We know that $\sqrt -17$ is not a real number. We cannot take the square root of negative numbers, because there is no number $a$ that, when multiplied by itself, will produce a negative number. In other words, $a^{2}\geq0$ (where $a$ is a real number).
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