Answer
$-28a^{6}b^{2}c^{6}$
Work Step by Step
Using the laws of exponents, the given expression, $
(-14a^5bc^2)(2abc^4)
$, simplifies to
\begin{array}{l}\require{cancel}
(-14)(2)a^{5+1}b^{1+1}c^{2+4}
\\\\=
-28a^{6}b^{2}c^{6}
.\end{array}
Intermediate Algebra (6th Edition)
by Martin-Gay, Elayn
Published by
Pearson
ISBN 10:
0321785045
ISBN 13:
978-0-32178-504-6
Chapter 7 - Section 7.1 - Radicals and Radical Functions - Exercise Set - Page 418: 96
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