Intermediate Algebra (6th Edition)

Published by Pearson
ISBN 10: 0321785045
ISBN 13: 978-0-32178-504-6

Chapter 7 - Section 7.1 - Radicals and Radical Functions - Exercise Set - Page 418: 94

Answer

$64y^{18}z^{21}$

Work Step by Step

We are given the expression $(4y^{6}z^{7})^{3}$. We can simplify this expression using the power rule, which holds that $(a^{m})^{n}=a^{m\times n}$ (where a is a real number, and m and n are integers). $(4y^{6}z^{7})^{3}=(4)^{3}\times(y^{6})^{3}\times(z^{7})^{3}=64y^{18}z^{21}$
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